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If a line with a slope of -5/4

passes

through the point (2, -1) and (A, −7),
what is the value of A?

1 Answer

3 votes

Final answer:

The value of A is 6.8 for the line with a slope of -5/4 that passes through the points (2, -1) and (A, -7), by using the slope formula and algebraic manipulation.

Step-by-step explanation:

To find the value of A for the line with a slope of -5/4 that passes through the points (2, -1) and (A, −7), we can use the slope formula which is (change in y) / (change in x) = slope, or (y2 - y1) / (x2 - x1). In this case, we have the two points (2, -1) and (A, −7).

To solve for A, the equation will be:

1. Substitute the known values into the slope formula: (-7 - (-1)) / (A - 2) = -5/4.

2. Simplify the numerator: (-7 + 1) / (A - 2) = -5/4.

3. Now, solve for A: (-6) / (A - 2) = -5/4.

4. Cross-multiply to get 4(-6) = -5(A - 2).

5. Solve the equation: -24 = -5A + 10.

6. Add 5A to both sides: -24 + 5A = 10.

7. Subtract 10 from both sides: 5A = 34.

8. Finally, divide by 5: A = 34/5.

9. The value of A is 6.8.

Therefore, the line with a slope of -5/4 passing through the points (2, -1) and (A, −7) will have the point A equal to 6.8.

User Dohashi
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