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A line passes through the point (4, -6) and has a slope of -6. Write an equation in slope-intercept form for this line.​

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Answer:

To write the equation of a line in slope-intercept form, we need two pieces of information: the slope of the line and a point that lies on the line.

Given that the line passes through the point (4, -6) and has a slope of -6, we can use the point-slope form of a line to write the equation. The point-slope form is given by:

y - y₁ = m(x - x₁)

where (x₁, y₁) is a point on the line and m is the slope of the line.

Plugging in the values we have:

y - (-6) = -6(x - 4)

Simplifying the equation, we get:

y + 6 = -6x + 24

To write the equation in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept, we need to isolate y on one side of the equation.

Subtracting 6 from both sides, we have:

y = -6x + 18

Therefore, the equation of the line passing through the point (4, -6) with a slope of -6 in slope-intercept form is y = -6x + 18.

Explanation:

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