Final answer:
To make a 0.470 M NaCl solution, you would need 3.432 grams of NaCl when preparing 125.0 mL of the solution.
Step-by-step explanation:
To calculate the mass of NaCl required to make a 0.470 M NaCl solution, you can use the formula molarity (M) = moles of solute / volume of solution (in liters).
First, convert the volume of solution to liters: 125.0 mL = 0.125 L. Then, use the formula M = moles of solute / volume of solution to calculate the moles of NaCl needed. Rearranging the formula, moles of solute = M * volume of solution. Plugging in the values, moles of NaCl = 0.470 mol/L * 0.125 L = 0.05875 mol.
Finally, multiply the moles of NaCl by the molar mass of NaCl to find the mass: mass = moles of NaCl * molar mass of NaCl = 0.05875 mol * 58.5 g/mol = 3.432 g. Therefore, you would need 3.432 grams of NaCl to make 125.0 mL of a 0.470 M NaCl solution.