Answer:
0.044 mol CaOH
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Writing Compounds
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
2.5 g CaOH
Step 2: Identify Conversions
[PT] Molar Mass of Ca - 40.08 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
Molar Mass of CaOH - 40.08 + 16.00 + 1.01 = 57.09 g/mol
Step 3: Convert
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
0.043791 mol CaOH ≈ 0.044 mol CaOH