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Graph the parabola. y=(x-3)^2-1

Graph the parabola. y=(x-3)^2-1-example-1

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Answer:

Explanation:

y = (x-3)²-1

This is the equation for an up-opening parabola with vertex (3,-1).

Find the x-intercepts:

0 = (x-3)²-1

(x-3)² = 1

x-3 = ±1

x = 4, 2

The graph crosses the x-axis at (4,0) and (2,0).

Find the y-intercept:

y = (0-3)²-1 = 8

The graph crosses the y-axis at (0,8).

Plot your four points (3,-1), (4,0), (2,0), (0,8). Draw an up-opening parabola through the points.

User ZLK
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