Final answer:
Quinn's power output while lifting a package with a force of 50 N to a height of 7 m in 5 seconds is 70 Watts. Power is calculated as work done divided by time taken.
Step-by-step explanation:
Quinn uses a force of 50 N to lift a package to a height of 7 m. The work done by Quinn in lifting the package can be calculated using the formula Work (W) = Force (F) × Distance (d), which in this case is W = 50 N × 7 m = 350 J (Joules).
Power (P) is the rate at which work is done, which can be expressed as P = Work done (W) / Time (t). Quinn takes 5 seconds to lift the package, so his power output is P = 350 J / 5 s = 70 W (Watts).
The calculation shows that Quinn's power output while lifting the package is 70 Watts. This measures how quickly he is able to do the work of lifting the package to the required height.