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a small block, with a mass of 0.25k g, starts from rest at the top of the apparatus shown above. it then slides without friction down the incline, around the loop and then onto the final level section on the right . it then slides without friction, its and sticks to a second identical block. the blocks continue to slide. the maximum height of the incline is 0.40 m and the radius of the loop is 0.10 m.

User DoomGoober
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Final answer:

The problem is a physics question involving conservation of energy and momentum, and dynamics, to solve for the speed of a block sliding down an incline, the force on it during a loop-the-loop, and its final velocity after it sticks to an identical block.

Step-by-step explanation:

The subject in question deals with the concepts of mechanics in Physics, where a block slides down an incline, goes through a loop-the-loop, and then collides and sticks to an identical block. The problem includes aspects of energy conservation, momentum conservation, and dynamics.

In this scenario, to find the speed of the block at the bottom of the incline (just before the loop), conservation of energy is used because there is no friction. The potential energy at the top is converted entirely into kinetic energy at the bottom. If the block sticks to another block of the same mass, the conservation of momentum can be applied to find the final velocity of the two blocks sticking together.

To calculate the force of the track on the block at the bottom of the loop, one would use the concept of centripetal force, which is provided by the normal force of the track. This can be calculated with the equation involving mass, velocity, and the radius of the loop.

User Syed Hamza Hassan
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