Question

On January 1 the temperature at noon was 7°F. By 10 p.m. the temperature had fallen to -9°F. The temperature dropped how many degrees from noon to 10 p.m.?

Answer 1

The temperature dropped 16 degrees Fahrenheit from noon when the temperature was 7°F, to 10 p.m. when it had fallen to -9°F.

Step-by-step explanation:

The student has asked about the change in temperature from noon to 10 p.m. when it fell from 7°F to -9°F. To find out how many degrees the temperature dropped, we subtract the final temperature from the initial temperature. So, the calculation would be the initial temperature (7°F) minus the final temperature (-9°F), which equals to a 16°F drop in temperature (7 - (-9) = 16).

Step-by-Step Explanation

1. Record the initial temperature at noon: 7°F.

2. Record the final temperature at 10 p.m.: -9°F.

3. Subtract the final temperature from the initial temperature: 7°F - (-9°F) = 7°F + 9°F = 16°F.

4. The temperature dropped 16 degrees Fahrenheit.