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Can you help me with math (triangles)? Do only question 6

Can you help me with math (triangles)? Do only question 6-example-1
User Tim Hall
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Answer:


\sf\\\textsf{There is a property of parallelogram that says

Here's a proof of the theorem. See the image as a reference.


\sf\\1.\ \textsf{In triangles AOB and BOC,}\\i.\ \angle OAD=\angle OCB\ (A)\ \ \ [\textsf{AD//BC, alternate angles}]\\ii.\ AD=BC\ (S)\ \ \ [\textsf{Opposite sides of parallelogram are equal.}]\\iii.\ \angle ODA=\angle OBC\ (A)\ \ \ [\textsf{AD//BC, alternate angles.}]\\iv.\ \triangle AOB\cong \triangle BOC\ \ \ [\textsf{By A.S.A. axiom}]\\\\2.\ AO=OC\ and\ BO=OD\ \ \ [\textsf{Corresponding sides of congruent triangles are}\\\textsf{equal.]}

Two figures are said to be congruent if they have same shape and size. Two figures are said to be similar if they have same shape.

Can you help me with math (triangles)? Do only question 6-example-1
User Md Azharuddin
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7.2k points
3 votes
AB = BC
10 = 10

AC = AB + BC = 10 + 10 = 20

BD = BE
20 = 20

DE = BD + BE

DE = 20 + 20

DE = 40
User Braddock
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7.8k points

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