Final answer:
Yes. The car is affected by the air drag with a force of 20,000 N. The car has an acceleration of 0 m/s² and the truck has an acceleration of 40 m/s².
Step-by-step explanation:
(a) The car is affected by the air drag. According to Newton's third law of motion, every action has an equal and opposite reaction. Therefore, when the truck experiences an oppositely directed air drag force, the car also experiences the same magnitude of air drag force in the opposite direction. So, the car is affected by a 20,000 N air drag force.
(b) To calculate the acceleration of both the car and the truck, we can use Newton's second law of motion, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
For the car, the net force acting on it is the force it exerts on the truck minus the air drag force:
Net force on car = 20,000 N - 20,000 N = 0 N
Since the net force on the car is zero, its acceleration is also zero.
For the truck, the net force acting on it is the force exerted by the car plus the air drag force:
Net force on truck = 20,000 N + 20,000 N = 40,000 N
Using Newton's second law, we can solve for the acceleration of the truck:
40,000 N = 1000 kg * a
a = 40,000 N / 1000 kg = 40 m/s²
Therefore, the car has an acceleration of 0 m/s² and the truck has an acceleration of 40 m/s².