213k views
2 votes
use the vertex(h,k) and apoint on the graph (x,y) to find the general form of the equation of quadratic function form of the equation of quadratic function A ,(h,k)=(2,5) (x,y)=(-4,3)?​

User Thefaj
by
7.4k points

1 Answer

3 votes

Final answer:

To find the general form of a quadratic equation given the vertex (2,5) and a point (-4,3), use the vertex form equation to solve for 'a', then expand and simplify to get the equation in general form.

Step-by-step explanation:

To find the general form of the equation of a quadratic function given a vertex (h,k) and a point on the graph (x,y), we use the vertex form of a quadratic equation, which is y = a(x - h)² + k, where a is a coefficient that affects the width and direction of the parabola.

With the vertex at (2,5), the equation becomes y = a(x - 2)² + 5. Now, we'll plug in the coordinates of the given point (-4,3) to solve for a. Substituting x with -4 and y with 3, we get 3 = a(-4 - 2)² + 5. Simplifying, 3 = a(36) + 5. To solve for a, subtract 5 from both sides and then divide by 36, resulting in a = -1/18.

Substitute a back into the vertex form to get the quadratic equation in vertex form: y = (-1/18)(x - 2)² + 5. To convert this into the general form ax² + bx + c, expand the equation and simplify.

User Hjuskewycz
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories