In triangle STR, with sides ST = 21.9, TR = 14.8, and SR = 16.2, sin T is 0.73, cos T is 0.67, and tan T is 1.09.
We are given that triangle BCA ~ triangle STR which means that BC = ST CA = TR and BA = SR and angle B = angle S , angleC = angleT and angle A = angle R.
We need to find the values of cos T, sin T, and tan T.
First we will find the values of sides of triangle STR
which are ST = 21.9 = BC
TR = 14.8 = CA and SR = 16.2 = AB .
Now that we have found the values of sides we can find the value of trigonometric ratios.
First we will find the value of
Sin T = perpendicular / hypotenuse
= SR / ST
= 16.2 / 21.9
= 0.73
CosT = base / hypotenuse
= RT / ST
= 14.8 / 21.9
= 0.67
TanT = perpendicular / base
= SR / RT
= 16.2 / 14.8
= 1.09
So , according to out calculations the value of sinT is equal to 0.73 , cosT = 0.67 and tanT = 1.09