Answer:
A) To write the expression x^2 - 2x - 6 in the form (x + c)^2 + d, we need to complete the square.
First, let's rewrite the expression:
x^2 - 2x - 6 = (x^2 - 2x + 1) - 1 - 6 = (x - 1)^2 - 7
From the above expression, we can see that the values of C and D are:
C = 1
D = -7
B) Now that we have the expression x^2 - 2x - 6 in the form (x + C)^2 + D, we can solve the equation x^2 - 2x - 6 = 0.
(x - 1)^2 - 7 = 0
(x - 1)^2 = 7
Taking the square root of both sides:
x - 1 = ±√7
Solving for x:
x = 1 ± √7
Therefore, the solutions to the equation x^2 - 2x - 6 = 0 are:
x = 1 + √7 and x = 1 - √7