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Assume that the given code runs without any errors and the value of variables used in the code are y1=22, y2=11, and y3=12. What will be the output of the following C++ code?

y1 = y2++;

y2 = --y3;

y3 = y1+y2+y3+++y2++;

cout << y1 << y2 << y3;

Select the correct option:

A. 111245

B. 111144

C. 111244

D. 111145

User Lsborg
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1 Answer

1 vote

Final answer:

After evaluating the given C++ code with the specified variable values, the output would be 111244. This result comes from a series of post-increment and pre-decrement operations on the variables.

Step-by-step explanation:

The student is asking what the output would be after executing a piece of C++ code with provided variable values. Let's evaluate the code step by step:

  • y1 = y2++; // Post-increment: y1 is assigned y2's value of 11, then y2 becomes 12.
  • y2 = --y3; // Pre-decrement: y3 is decremented to 11, then assigned to y2.
  • y3 = y1+y2+y3+++y2++; // This line involves both pre and post-increments/decrements. Evaluate operands before and after the assignment: y1 (11) + y2 (11) + y3 (11, then incremented to 12) + y2 (post-incremented from 11 but original 11 used) equals 44, then y2 becomes 12.

Now printing the variables y1, y2, and y3:

  • y1 is 11 (from the value of y2 post-incremented).
  • y2 is 12 (11 pre-decremented from y3 then incremented).
  • y3 is 44 (sum of the above operations).

Hence, the output written by the statement cout << y1 << y2 << y3; would be 111244.

User UncleBob
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