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To create a legitimate probability distribution for the discrete random variable X with possible values of -3, -1, 3, 5, and 6, you need to assign probabilities to these values that satisfy the following conditions: 1. Each probability must be non-negative.

2. The sum of all probabilities must equal 1. You'll need to fill in the P(X=x) values for each of the possible values -3, -1, 3, 5, and 6 while ensuring they meet these conditions.

User ManneR
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Final answer:

To create a legitimate probability distribution for the discrete random variable X with possible values of -3, -1, 3, 5, and 6, you need to assign probabilities to these values that satisfy the conditions of non-negativity and summing to 1.

Step-by-step explanation:

To create a legitimate probability distribution for the discrete random variable X with possible values of -3, -1, 3, 5, and 6, you need to assign probabilities to these values that satisfy the following conditions:

  1. Each probability must be non-negative.
  2. The sum of all probabilities must equal 1.

An example of a legitimate probability distribution for X could be:

  • P(X=-3) = 0.1
  • P(X=-1) = 0.2
  • P(X=3) = 0.4
  • P(X=5) = 0.1
  • P(X=6) = 0.2

These probabilities are all non-negative and their sum is equal to 1. This is a valid probability distribution for X.

User Pierre Valade
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