Final answer:
The closed formulas for the given sequences are An = 3 + (n-1)(2), Bn = (2 * n)/(n+1), Dn = (-1)n+1, and En = 1/n.
Step-by-step explanation:
a) To find a closed formula for sequence A, observe that the sequence increases by 3, then 5, then 7, and so on. This means that the nth term of the sequence can be calculated using the formula: An = 3 + (n-1)(2).
b) For sequence B, notice that the numerator doubles with each term, while the denominator increases by 1. So, the nth term of the sequence can be expressed as: Bn = (2 * n)/(n+1).
c) The pattern in sequence D repeats the numbers -1 and 1. Since the sequence alternates every term, we can use the formula: Dn = (-1)n+1.
d) Sequence E consists of the reciprocals of the positive integers. So, the nth term can be represented as: En = 1/n.