Final answer:
This response confirms that in modular arithmetic, if two pairs of integers are congruent modulo a positive integer n, then both their sums and products will also be congruent modulo n.
Step-by-step explanation:
The question concerns the properties of congruence classes in modular arithmetic. Using the definition [a]n = a + nk , where a, a', b, and b' are integers and n is a positive integer, we need to demonstrate that if [a]n = [a']n and [b]n = [b']n, then [a+b]n = [a'+b']n and [ab]n = [a'b']n.
To start, since a is congruent to a' modulo n and b is congruent to b' modulo n, it follows that there exist integers k and j such that a' = a + nk and b' = b + nj. For addition, we have a' + b' = (a + nk) + (b + nj) = (a + b) + n(k+j), which is in the set [a+b]n. For multiplication, we get a'b' = (a + nk)(b + nj) = ab + nbj + nak + n2kj = ab + n(bj + ak + nkj), which means a'b' is in the set [ab]n. Thus, the properties are proven.