Question

An antiproton (same properties as a proton except that q=−e ) is moving in the combined electric and magnetic fields of the figure.(Figure 1) Assume that B = 2.9 T and E = 1000 V/m .

What is the magnitude of the antiproton's acceleration at this instant?
Express your answer with the appropriate units.

Answer 1

To find the magnitude of the antiproton's acceleration, you can use the equation for the force on a charged particle moving in both electric and magnetic fields. Plugging in the given values, you can calculate the acceleration of the antiproton.

Step-by-step explanation:

To find the magnitude of the antiproton's acceleration, we can use the equation for the force on a charged particle moving in both electric and magnetic fields. The force on the antiproton is given by: F = q(E + v x B), where q is the charge of the antiproton,

E is the electric field, v is the velocity of the antiproton, and B is the magnetic field. Since the antiproton has a charge of -e, and it is moving perpendicular to both the electric and magnetic fields, the force simplifies to: F = -e(vB). The acceleration of the antiproton is given by a = F/m, where m is the mass of the antiproton. Plugging in the given values for B and E, and using the known mass of the antiproton, the acceleration can be calculated.