Final answer:
To prove that if A ⊆ B, then (A ∪ C) ⊆ (B ∪ C), we need to show that every element in (A ∪ C) is also in (B ∪ C).
Step-by-step explanation:
To prove that if A ⊆ B, then (A ∪ C) ⊆ (B ∪ C), we need to show that every element in (A ∪ C) is also in (B ∪ C).
Let x be an arbitrary element in (A ∪ C). This means that x is in either A or C (or both).
If x is in A, since A ⊆ B, x is also in B. Thus, x is in (B ∪ C).
If x is in C, then x is also in (B ∪ C) since C is a subset of (B ∪ C).
Therefore, every element in (A ∪ C) is also in (B ∪ C), which proves that if A ⊆ B, then (A ∪ C) ⊆ (B ∪ C).