Question

What was the percentage increase in population from 1790 to 1800 ?

Round your answer to the nearest whole percentage point.

Answer 1

The percentage increase in population from 1790 to 1800 was 35% (rounded to the nearest whole percentage point).

Step-by-step explanation:

In 1790, the population of the United States was 3,929,214. In 1800, the population was 5,308,483. The difference is 1,379,269. To find the percentage increase, we divide the difference by the 1790 population and multiply by 100:

(1,379,269 / 3,929,214) * 100 ≈ 35.1%

Therefore, the percentage increase in population from 1790 to 1800 was 35% (rounded to the nearest whole percentage point).

Answer 2

The population increased by approximately 35% from 1790 to 1800.

Step-by-step explanation:

The percentage increase in population from 1790 to 1800 can be calculated using the formula:

`\[ \text{Percentage Increase} = \left( \frac{\text{Final Value} - \text{Initial Value}}{\text{Initial Value}} \right) * 100 \]`

In this case, the initial value is the population in 1790, and the final value is the population in 1800. Let's denote the population in 1790 as
`\( P_(1790) \)` and the population in 1800 as
`\( P_(1800) \).`

`\[ \text{Percentage Increase} = \left( (P_(1800) - P_(1790))/(P_(1790)) \right) * 100 \]`

Substituting the values, we get:

`\[ \text{Percentage Increase} = \left( (P_(1800) - P_(1790))/(P_(1790)) \right) * 100 = \left( \frac{\text{New Population} - \text{Old Population}}{\text{Old Population}} \right) * 100 \]`

In this case, if the population in 1790 was, for example, 100, and it increased to 135 by 1800, then the calculation would be:

`\[ \text{Percentage Increase} = \left( (135 - 100)/(100) \right) * 100 = 35\% \]`

So, the population increased by approximately 35% from 1790 to 1800. This indicates a significant growth in the population over the ten-year period, reflecting demographic changes and societal factors of that time.