124k views
4 votes
Estimate de Fourier coefficients and series for the function g:[−π,π]→R defined by g(x)=∣x∣. Is the Fourier series point-wise or uniform convergent to something?

1 Answer

3 votes

Final answer:

The Fourier series coefficients for the function g(x) = |x| on the interval [-π,π] can be estimated using the formulas for a₀, aₙ, and bₙ. The resulting Fourier series for g(x) is point-wise convergent to the function |x|, but it is not uniformly convergent.

Step-by-step explanation:

The Fourier coefficients of the function g(x) = |x| on the interval [-π,π] can be determined by using the formula:

a₀ = (1/π) ∫[-π,π] |x| dx = (2/π) ∫[0,π] x dx = 1

aₙ = (1/π) ∫[-π,π] |x| cos(nx) dx = (2/π) ∫[0,π] x cos(nx) dx = (-2/πn²)(-1)ⁿ + (2/πn²)

bₙ = (1/π) ∫[-π,π] |x| sin(nx) dx = 0

To estimate the Fourier series for g(x), we can use the formula:

g(x) = (a₀/2) + Σ(aₙ cos(nx) + bₙ sin(nx))

Since the function g(x) = |x| is an odd function, all the cosine terms (aₙ) will be zero. Therefore, the Fourier series for g(x) simplifies to:

g(x) = (1/2) + Σ((2/πn²)sin(nx))

The Fourier series for g(x) is point-wise convergent to the function |x|, but it is not uniformly convergent.

User Webnesto
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories