Final answer:
To solve the initial value problem y' =(x+y-4)² with y(0)=0, you can use the substitution u = x+y-4. After the substitution, the differential equation becomes u' = (u)². The solution to the original initial value problem is described by the equation y = x + u - 4.
Step-by-step explanation:
To solve the initial value problem y′ =(x+y−4)² with y(0)=0,
a. We can use the substitution u = x+y-4. Taking the derivative using prime notation, we get u′ = 1+y′.
b. After the substitution, the differential equation becomes u′ = (u)².
c. The solution to the original initial value problem is described by the equation y = x + u - 4.