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A) (x₁,y₁,z₁) + (x₂,y₂,z₂) = (x₁+x₂,y₁ +y₂,z₁+z₂)

c(x,y,z) = (0,cy,cz)
A.The set is a vector space.
B. The set is not a vector space because the associative property of addition is not satisfied.
C. The set is not a vector space because it is not closed under scalar multiplication.
D. The set is not a vector space because the associative property of multiplication is not satisfied.
E. The set is not a vector space because the multiplicative identity property is not satisfied.

User Ognyan
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1 Answer

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Final answer:

The set given by the vector operation c(x,y,z) = (0,cy,cz) is not a vector space due to the lack of closure under scalar multiplication, thus the correct answer is C. The essential properties of a vector space, such as associative and commutative properties, are clearly defined and must apply to all vector components.

Step-by-step explanation:

The question pertains to whether a given set satisfies the properties of a vector space. For a set to be a vector space, several conditions must be met, including closure under vector addition and scalar multiplication, the associative and commutative properties of vector addition, and the existence of a multiplicative identity. Given the operation c(x,y,z) = (0,cy,cz), the set does not satisfy the scalar multiplication property of a vector space because multiplying a vector by a scalar should affect all components, not just the latter two. Therefore, the correct choice is C. The set is not closed under scalar multiplication because the scalar c does not affect the x-component of the vector as it should in a vector space.

To verify that the order of addition does not affect the sum of three vectors, one could take vectors A, B, and C and show that A+B+C equals the sum obtained with any other order of addition. This demonstrates the commutative property of vector addition: A+B = B+A. Scalar multiplication by a sum of vectors is distributive, which is a crucial property of vector spaces. While dealing with the components of vectors, we should consider the distributive property to understand operations like the dot product or the cross product.

User Joshua Ulrich
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