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It is estimated that t months from now the population of a small town in Michigan will be increasing at the rate of r(t)=4+5t²/³ people per month. If the current population is 15,000 people, what will the population be 8 months from now? Hint: First find the function P(t) that gives the population of the town as a function of time t.

User Jhnath
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Final answer:

To determine the population 8 months from now, integrate the rate function r(t) and add the result to the initial population of 15,000. After integrating and applying the initial condition, the town's population will be 15,112 people 8 months from now.

Step-by-step explanation:

The student's question involves the use of calculus, specifically integrating a rate of change to find a function that represents the total population P(t) over time. To find the population 8 months from now, we need to integrate the rate function r(t) = 4 + 5t²/³ people per month. The integration will yield the population as a function of time P(t), which will then be added to the initial population of 15,000 people.

The population at any time t months from now is given by the integral of the rate of change of population, which is:

P(t) = ∫(4 + 5t²/³)dt

Performing the integration, we obtain:

P(t) = 4t + ¾5tµ/³ + C

Since the population at time 0 (current population) is 15,000, we set t = 0 to find C:

15,000 = C

Therefore, P(t) = 4t + ¾5tµ/³ + 15,000

Now we can find the population 8 months from now by substituting t = 8 into P(t):

Population after 8 months = 4(8) + ¾5(8)µ/³ + 15,000

P(8) = 32 + 20(4) + 15,000

P(8) = 32 + 80 + 15,000

P(8) = 15,112 people

Hence, the population of the small town in Michigan will be 15,112 people 8 months from now.

User Nowayyy
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