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A builder owns a triangular-shaped lake lot that has a road frontage (base) of 76 feet and a depth of 125 feet. What is the area of the lot?

A. None of the answers listed.
B. 4,750 square feet
C. 277 square feet
D. 9,500 square feet

User Peti
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1 Answer

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Final answer:

Using the area formula for a triangle, the area of the triangular lot with a base of 76 feet and height of 125 feet is calculated to be 4,750 square feet.

Step-by-step explanation:

The question is asking for the area of a triangular lot, given its base and height (road frontage and depth respectably). To calculate the area of a triangle, the formula is Area = ½ × base × height. In this scenario, the base is 76 feet, and the height is 125 feet.

Applying the formula, we get:

Area = ½ × 76 ft × 125 ft

Area = 38 ft × 125 ft

Area = 4,750 square feet

Therefore, the area of the lot is 4,750 square feet, which makes option B the correct answer.

User Thelandog
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