Final answer:
To find the Laplace transform of the given function, apply the formula L[∫ᵗ₀ g(u)du]=L[g]/s and simplify the integral.
Step-by-step explanation:
To find the Laplace transform of the given function, we can use the formula L[∫ᵗ₀ g(u)du]=L[g]/s. In this case, the function is f(t)=t∫ᵗ₀ e⁻ᵘ u² du. Let's find the Laplace transform by applying the formula and simplifying the integral:
- Apply the formula: L[f(t)] = L[t∫ᵗ₀ e⁻ᵘ u² du] = 1/s * L[∫ᵗ₀ e⁻ᵘ u² du]
- Simplify the integral: L[∫ᵗ₀ g(u)du] = L[g]/s = 1/s * L[e⁻ᵘ u² du]
- Apply the Laplace transform to the integral: L[e⁻ᵘ u² du] = 1/(s+1)³
- Substitute the result back into the equation: L[f(t)] = 1/s * 1/(s+1)³
So, the Laplace transform of the given function is 1/s * 1/(s+1)³.