Question

The Boolean expression ((A and B) and (not (A and B)) evaluates to: false in all cases. true in all cases. true whenever both A is true and B is true. true whenever only A is true or only B is true. Question 2 (2 points) Consider variable x which is an int where x = 0, which statement below will be true after the following loop terminates? while (x < 100) { x *= 2; } X == 2 The loop won't terminate. It's an infinite loop. X == 98 X == 0 0

Answer 1

The Boolean expression evaluates to false in all cases due to the contradictions within the expression, and the loop creates an infinite loop since the value of x will always remain 0 and never reach 100.

Step-by-step explanation:

The Boolean expression ((A and B) and (not (A and B))) evaluates to false in all cases. This is because the expression inside the first set of parentheses (A and B) can either be true or false, but the not operator then makes (not (A and B)) the opposite value of (A and B), so when they are ANDed together, the result will always be false.

Regarding the loop involving variable x, since x is initially set to 0, the statement x < 100 is true. However, on the first pass through the loop, the statement x *= 2 will be executed, which will keep x at 0 because 0 multiplied by 2 is still 0. Since x will never change from 0, it will never reach 100, and hence, the loop will not terminate, creating an infinite loop.