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"In the following reaction between potassium superoxide and carbon dioxide, how many moles of O2 are produced when 0.400 mol of KO2 reacts?

4KO₂(s) + 2CO₂(g) → 2K₂CO₃(s) + 3O₂(g)

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Final answer:

0.300 moles of O₂ are produced when 0.400 mol of KO₂ reacts with carbon dioxide.

Step-by-step explanation:

In the given reaction:

4KO₂(s) + 2CO₂(g) → 2K₂CO₃(s) + 3O₂(g)

From the balanced equation, we can see that for every 4 moles of KO₂ reacted, 3 moles of O₂ are produced. Therefore, to find the number of moles of O₂ produced when 0.400 mol of KO₂ reacts, we can set up the following ratio:

(0.400 mol KO₂) / (4 mol KO₂) = (x mol O₂) / (3 mol O₂)

By solving for x, we find that 0.300 moles of O₂ are produced.

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