Question

"How many moles of NH3 can be produced by the reaction of 2.0 mol of N2 with 3.0 mol of H2 via the equation below? Hint: There is a limiting reactant.

N2(g) + 3H2(g) → 2NH3(g)"

Answer 1

The reaction can produce 4.0 moles of NH3 from 2.0 moles of N2.

Step-by-step explanation:

The balanced chemical equation for the reaction is:

N2(g) + 3H2(g) → 2NH3(g)

From the coefficients of the balanced equation, we can determine the mole ratio between N2 and NH3. The equation shows that for every 1 mole of N2, 2 moles of NH3 are produced. Therefore, if we have 2.0 moles of N2, we can calculate the moles of NH3 produced as follows:

(2.0 mol N2) x (2 mol NH3 / 1 mol N2) = 4.0 mol NH3

Therefore, 4.0 moles of NH3 can be produced from the reaction.