Final answer:
The energy found in one photon of visible light with a wavelength of 589 nm is 3.37 x 10^-19 J. Hence the correct answer is option C
Step-by-step explanation:
The energy of a photon can be calculated using the formula: E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the photon. To calculate the energy of a photon of visible light with a wavelength of 589 nm, we need to first determine the frequency using the formula: c = λf, where c is the speed of light (3.00 x 10^8 m/s) and λ is the wavelength. Rearranging this equation, we get f = c/λ. Substituting the values, we get f = (3.00 x 10^8 m/s)/(589 x 10^-9 m) = 5.09 x 10^14 Hz. Now, plugging this frequency value into the energy equation, we get: E = (6.626 x 10^-34 J·s) x (5.09 x 10^14 Hz) = 3.37 x 10^-19 J.
Therefore, the energy found in one photon of visible light with a wavelength of 589 nm is 3.37 x 10^-19 J.
Hence the correct answer is option C