Final answer:
a) N(5) represents the amount of glass still in use after 5 years and is equal to 2206.28 lb. b) N'(5) represents the rate at which the amount of glass still in use is changing after 5 years and is equal to -1988.74 lb/year. c) 4% of the original amount of glass will still be in use after approximately 21.37 years.
Step-by-step explanation:
a) To find N(5), we need to substitute t=5 into the equation N(t) = 200,000(0.406). N(5) = 200,000(0.406)^5 = 2206.28 lb. N(5) represents the amount of glass still in use after 5 years.
b) N'(t) represents the rate of change of N(t). To find N'(5), we need to differentiate N(t) with respect to t. N'(t) = 200,000(0.406)(ln(0.406))(0.406)^t. N'(5) = 200,000(0.406)(ln(0.406))(0.406)^5 = -1988.74 lb/year. N'(5) represents the rate at which the amount of glass still in use is changing after 5 years.
c) We want to find the value of t when 4% of the original amount is still in use. This means we need to find t such that N(t) = 0.04 * 200,000. Solving for t, we have 200,000(0.406)^t = 0.04 * 200,000. Simplifying, (0.406)^t = 0.04. Taking the natural logarithm of both sides, t ln(0.406) = ln(0.04). Solving for t, t = ln(0.04) / ln(0.406) = 21.37 years.