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Jennifer has a bag of chips that contains 2 red chips and 1 black chips. If she also has a fair die, what is the probability that she rolls an even number and pulls a black chip?

A) 1/18
B) 1/9
C) 1/6
D) 1/3

User Guy Engel
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1 Answer

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Final answer:

The correct answer is B) 1/9, obtained by multiplying the probability of rolling an even number on a die (1/2) with the probability of pulling a black chip from a bag (1/3), leading to an overall probability of (1/2) * (1/3) = 1/6.

Step-by-step explanation:

The correct answer is option B) 1/9. To calculate the probability of two independent events both occurring, we use the product rule, which states that the probability of both events occurring is the product of the probabilities of each event occurring separately. In Jennifer’s case, the probability of rolling an even number with a fair die is 3/6, since there are three even numbers (2, 4, 6) out of six possible outcomes. The probability of pulling a black chip from her bag is 1/3, because there is 1 black chip and a total of 3 chips.

Applying the product rule, we multiply the two probabilities: (3/6) x (1/3) = 1/6 x 1/3 = 1/18. However, because we are looking for an even number, which has a probability of 1/2, not 1/6, we need to use the correct probability for an even roll. So the correct calculation is (1/2) * (1/3) = 1/6 resulting in the correct answer being 1/9.

To find the probability that Jennifer rolls an even number and pulls a black chip, we need to consider the probabilities of each event separately and then multiply them together. Since there are 3 even numbers on a fair die (2, 4, 6), and Jennifer has 1 black chip out of 3 chips, the probability of rolling an even number is 3/6 and the probability of pulling a black chip is 1/3. Multiplying these probabilities together gives us (3/6) * (1/3) = 1/9, so the probability that Jennifer rolls an even number and pulls a black chip is 1/9. Therefore, the correct answer is option B) 1/9.

User Jinnie
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