Question

Select the correct answer.

The force of attraction between two like charged table tennis balls is 2.4 x 105 newtons. If the charge on the one is 3.8 x 108 coulombs and on the
other is 3.0 x 10-8 coulombs, what is the distance between the two charges? (k = 9.0 x 10° newton-meter2/coulombs²)
O A 0.11 meters
OB. 0.24 meters
O C. 0.45 meters
O D. 0.65 meters

Answer 1

The distance between the charges is approximately 0.11 meters. The correct answer is option: A 0.11 meters

Step-by-step explanation:

To find the distance between two charges, we can use Coulomb's Law, which states that the force between two charges is equal to the product of their magnitudes divided by the square of the distance between them. The formula for Coulomb's Law is:

F = (k * q1 * q2) / r^2

Where:

F is the force of attraction or repulsion between the charges,

k is the electrostatic constant (9.0 × 10^9 Nm^2/C^2),

q1 and q2 are the magnitudes of the charges, and

r is the distance between the charges.

In this case, the force is given as 2.4 x 10^5 N, and the charges on the two balls are 3.8 x 10^8 C and 3.0 x 10^-8 C. We can rearrange the formula to solve for the distance:

r = sqrt((k * q1 * q2) / F)

Plugging in the values:

r = sqrt((9.0 × 10^9 Nm^2/C^2 * 3.8 x 10^8 C * 3.0 x 10^-8 C) / (2.4 x 10^5 N))

r ≈ 0.11 meters