Question

Express the following concentration of solution in terms of molarity: 3.00 L of solution contains 1.75 mol of solute.

a. 5.25 M

b. 0.583 M

c. 1.71 M

d. too little information to know

Answer 1

The molarity of a solution with 1.75 moles of solute in 3.00 liters of solution is calculated by dividing the number of moles by the volume in liters, resulting in a molarity of 0.583 M, which corresponds to option b.

Step-by-step explanation:

To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters. Molarity is defined as the number of moles of solute per liter of solution (mol/L).

For the given solution containing 1.75 moles of solute in 3.00 liters of solution, the molarity (M) is calculated as follows:

Moles of solute = 1.75 mol
Volume of solution = 3.00 L

The molarity is calculated by dividing the moles of solute by the volume of the solution in liters:

Molarity (M) = Moles of solute / Volume of solution in liters
Molarity (M) = 1.75 mol / 3.00 L
Molarity (M) = 0.583 M

Therefore, the concentration of the solution is 0.583 M, which is option b.