Final answer:
To prepare 1500 mL of 0.200 M HCl solution from 6.00 M HCl, we need 50.0 mL of the concentrated acid based on the dilution formula M1V1 = M2V2. We rearrange the formula and calculate to find the required volume.
Step-by-step explanation:
To find the volume of 6.00 M HCl required to prepare 1500 mL (or 1.500 L) of a 0.200 M HCl solution, we can use the dilution formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution.
Step 1: Identify the known variables:
M1 = 6.00 M (initial concentration of the stock solution),
M2 = 0.200 M (final concentration of the solution),
V2 = 1500 mL or 1.500 L (final volume of the solution).
Step 2: Rearrange the dilution formula to solve for V1:
V1 = (M2V2) / M1.
Step 3: Substitute the known values into the formula and calculate V1:
V1 = (0.200 M * 1.500 L) / 6.00 M = 0.0500 L.
Since 0.0500 L is equal to 50.0 mL, the volume of 6.00 M HCl needed is 50.0 mL.