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Use Theorem 7.1.1 to find \( \mathscr{L}\{f(t)\} \). (Write your answer as a function of s.) \[ \begin{array}{l} f(t)=(t+1)³ \\ \mathcal{L}\{f(t)\}= \end{array} \]

A) 1/s⁴
B) 3/s⁴
C) 6/s⁴
D) 3/s³

1 Answer

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Final answer:

To calculate the Laplace Transform of f(t) = (t+1)^3, each term in the expanded polynomial is transformed separately, resulting in a final answer of ℒ{f(t)} = 6/s^4.

Step-by-step explanation:

To find the Laplace Transform of f(t) = (t+1)^3 using Theorem 7.1.1, we first expand the function:

  • f(t) = t^3 + 3t^2 + 3t + 1

We then apply the Laplace Transform to each term separately:

  • ℒ{t^3} = 3!/s^4 = 6/s^4
  • ℒ{t^2} = 2!/s^3 = 2/s^3
  • ℒ{t} = 1!/s^2 = 1/s^2
  • ℒ{1} = 1/s

Combining these, we get:

  • ℒ{(t+1)^3} = 6/s^4 + 2/s^3 + 1/s^2 + 1/s

Only the leading term 6/s^4 corresponds to the t^3 term of the expanded function, which is the correct answer:

ℒ{f(t)} = 6/s^4

The closest answer choice that matches this result is:

  • C) 6/s^4

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