Final answer:
To calculate the Laplace Transform of f(t) = (t+1)^3, each term in the expanded polynomial is transformed separately, resulting in a final answer of ℒ{f(t)} = 6/s^4.
Step-by-step explanation:
To find the Laplace Transform of f(t) = (t+1)^3 using Theorem 7.1.1, we first expand the function:
- f(t) = t^3 + 3t^2 + 3t + 1
We then apply the Laplace Transform to each term separately:
- ℒ{t^3} = 3!/s^4 = 6/s^4
- ℒ{t^2} = 2!/s^3 = 2/s^3
- ℒ{t} = 1!/s^2 = 1/s^2
- ℒ{1} = 1/s
Combining these, we get:
- ℒ{(t+1)^3} = 6/s^4 + 2/s^3 + 1/s^2 + 1/s
Only the leading term 6/s^4 corresponds to the t^3 term of the expanded function, which is the correct answer:
ℒ{f(t)} = 6/s^4
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