Question

A football is kicked vertically upward from a height of 3 feet with an initial speed of 45 feet per second. The formula h=3+45t-16t^2 describes the balls height above the ground, h, in feet, t in seconds after it was kicked. Use this formula to find the balls height 2 seconds after it was kicked

Answer 1

The balls height 2 seconds after it was kicked is 29 feet.

Explanation:

To find the ball's height 2 seconds after it was kicked, substitute (t = 2) into the given formula (h = 3 + 45t - 16t^2):

h = 3 + 45(2) - 16(2)^2

First, calculate the terms within the parentheses:

h = 3 + 90 - 16(4)

Now, perform the exponentiation and multiplication:

h = 3 + 90 - 64

Combine like terms:

h = 93 - 64

Finally, subtract:

h = 29

So, the ball's height 2 seconds after it was kicked is 29 feet.

The positive value of h indicates the height above the ground, and the result aligns with expectations, as the ball reaches its highest point before descending.

Therefore, 29 feet is the height of the football 2 seconds after it was kicked.