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Imate the real solutions to the quadratic equat 1.09x²+2.05x-1.035=0 d

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Final answer:

The quadratic equation given is 1.09x² + 2.05x - 1.035 = 0, which can be solved using the quadratic formula. The solutions provided are x = -.0024 and x = .00139, but the context of the problem implies that only x = .00139 is a suitable real-life solution.

Step-by-step explanation:

The question is asking to solve a quadratic equation using the quadratic formula. A quadratic equation is generally represented in the form ax² + bx + c = 0, where a, b, and c are constants.

To find the solutions for x, we use the quadratic formula x = (-b ± √(b² - 4ac)) / (2a). In this case, we're given the equation 1.09x² + 2.05x - 1.035 = 0. However, since the answer seems to be already provided as x = -.0024, or x = .00139, we have to verify which solution is correct.

The statement suggests that .001-.0024 is a negative situation which cannot happen in real life, leading to the conclusion that the actual value of x is .00139. This method of determining the correctness of solutions based on real-life applicability is sometimes used when the context of a problem places constraints on the possible values of x.

User Franc Weser
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