The axis of symmetry for the function y=(x-3)^2-5 is the vertical line x=3. This is determined by the vertex form of the quadratic equation, which shows the axis of symmetry at x=h where h is from the term (x-h).
The question seeks to determine the axis of symmetry for the given quadratic function y=(x-3)^2-5. A quadratic function of the form y=a(x-h)^2+k has its axis of symmetry at the line x=h. In this case, since the function is y=(x-3)^2-5, the axis of symmetry is at x=3. This line represents a vertical line through the vertex of the parabola, which divides it into two mirror-image halves.
So, the axis of symmetry for the function y=(x-3)^2-5 is the vertical line x=3.