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A mass weighing 16 pounds stretches a spring 0.5 feet. The

internal friction of the system imparts a damping force numerically
equal to the instantaneous velocity. If the mass is released from
the equation

1 Answer

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Final answer:

To determine the distance that the object travels when released from a certain distance from equilibrium, we can use the principles of simple harmonic motion (SHM) and Newton's laws of motion. By considering the force exerted by the spring and the frictional force acting on the object, we can calculate the total distance traveled.

Step-by-step explanation:

In this question, we are given a 0.5-kg object connected to a spring. We are told that there is friction between the object and the surface, with a coefficient of friction of 0.06. The object is released from 0.2 m away from equilibrium. We need to determine the distance that the object travels.

To solve this problem, we can use the principles of simple harmonic motion (SHM) and Newton's laws of motion. We know that in SHM, the restoring force exerted by the spring is proportional to the displacement from equilibrium. We can calculate the force exerted by the spring using Hooke's Law, which states that the force is equal to the spring constant multiplied by the displacement.

Additionally, we need to take into account the frictional force acting on the object. The frictional force is given by the coefficient of friction multiplied by the normal force, which is equal to the weight of the object in this case. We can use the frictional force to calculate the acceleration of the object using Newton's second law.

Using the equations of SHM, we can determine the total distance that the object travels from its released position.

User Kay Gladen
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