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Given the quadratic function f(x)=0.20x²-1.6x-1.

A)Find x and y intercepts algebraically.
B)Find the vertex form of f.
C)Find the vertex and the maximum or minimum.

1 Answer

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Final answer:

To find the x and y intercepts of the quadratic function, you set the other variable to zero and solve. The vertex form is found by completing the square, and the vertex can be identified as a minimum or maximum based on the sign of the coefficient of x². In this function, the vertex is a minimum.

Step-by-step explanation:

To find the x and y intercepts algebraically for the quadratic function f(x) = 0.20x² - 1.6x - 1, we set y and x to zero respectively and solve the equations.

To find the vertex form of f, we complete the square. The formula for vertex form is f(x) = a(x - h)² + k, where (h, k) is the vertex.

For the vertex and whether it is a maximum or minimum, we look at the coefficient of . If a is positive, the parabola opens upwards, and the vertex is a minimum. If a is negative, the parabola opens downwards, and the vertex is a maximum. Since the coefficient of in f(x) is positive (0.20), the vertex represents a minimum.

To find the exact value of the vertex, we use the formula h = -b/(2a) and k = f(h). Inserting the values into the formula gives us the coordinates of the vertex.

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