Final answer:
The zeros of the function f(x) are -4, 2, and 1.
Step-by-step explanation:
Given that x = -4 is one of the zeros of the function f(x) = -x³ + x² + 16x - 16, we can use polynomial division to find the quadratic equation that corresponds to the remaining zeros.
By dividing f(x) by (x + 4), we get the quadratic equation x² - 3x + 4 = 0. We can solve this equation using the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
Plugging in the values a = 1, b = -3, and c = 4, we get two possible values for x: x = 2 and x = 1. Therefore, the zeros of the function f(x) are -4, 2, and 1.
This formula will provide us with the two other solutions (if they are real numbers), thus finding all possible zeros of the polynomial function.