Question

84.9 g of solid iron reacts with oxygen gas forming iron(III) oxide. How many moles of oxygen will react

Answer 1

1.14 moles of oxygen will react

Step-by-step explanation:

The balanced equation of reaction between iron and oxygen is

4 Fe + 3 O₂ → 2 Fe₂O₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

• Fe: 4 moles
• O₂: 3 moles
• Fe₂O₃: 2 moles

The molar mass of iron being Fe 55.85 g/mole, then the following amount of mass reacts by stoichiometry: 4 moles* 55.85 g/mole=223.4 g

You can apply the following rule of three: if by stoichiometry 223.4 grams of Fe react with 3 moles of O₂, 84.9 grams of Fe react with how many moles of O₂?

`moles of O_(2) =(84.9 grams of Fe*3 moles ofO_(2) )/(223.4 grams of Fe)`

moles of O₂= 1.14 moles

1.14 moles of oxygen will react