Final answer:
To calculate the mass of 4.76 mol of copper (II) sulphate pentahydrate, multiply the molar mass (which is 249.68 g/mol) by the number of moles to get 1189.06 grams.
Step-by-step explanation:
To calculate the mass of 4.76 mol of copper (II) sulphate pentahydrate, CuSO₄·5H₂O, we first need to determine its molar mass.
The molar mass is the sum of the atomic masses of each element in the compound, multiplied by the number of atoms of that element in the formula. Copper (II) sulphate pentahydrate includes one copper atom (Cu), one sulfur atom (S), four oxygen atoms (O) in the sulphate ion, and five water molecules (5H₂O).
The atomic masses from the periodic table are approximately: Cu = 63.55 g/mol, S = 32.07 g/mol, O = 16.00 g/mol (for each atom of oxygen), and H = 1.008 g/mol.
The molar mass of copper (II) sulphate pentahydrate can be calculated as follows:
(1 × 63.55 g/mol) + (1 × 32.07 g/mol) + (4 × 16.00 g/mol) + (10 × 1.008 g/mol) = 249.68 g/mol
Now, to find the mass in grams of 4.76 mol of CuSO₄·5H₂O, we multiply the molar mass by the number of moles:
(4.76 mol) × (249.68 g/mol) = 1189.06 grams