Question

The weight % of S in K₂SO₄ is

a. 14.2%

b. 18.4%

c. 54.4%

d. 22.4%

Answer 1

The weight % of S (sulfur) in K₂SO₄ (potassium sulfate) is not given in the options provided.

Step-by-step explanation:

The weight % of S (sulfur) in K₂SO₄ (potassium sulfate) can be calculated using the formula:

Weight % of S = (Mass of S / Mass of K₂SO₄) x 100%

Since there are 2 atoms of S in K₂SO₄, the molar mass of S is 32 g/mol. The molar mass of K₂SO₄ is 174 g/mol. Therefore, the mass of S in K₂SO₄ is 2 x 32 g/mol = 64 g/mol.

Weight % of S = (64 g/mol / 174 g/mol) x 100% ≈ 36.8%

Therefore, the correct weight % of S in K₂SO₄ is not given among the options.

Answer 2

B. 18.4%

Step-by-step explanation:

Molar mass of potassium (K) = 39.10 g/mol

Molar mass of sulfur (S) = 32.06 g/mol

Molar mass of oxygen (O) = 16.00 g/mol

Molar mass of K2SO4 = 2 × molar mass of K + molar mass of S + 4 × molar mass of O.

= 2 × 39.10 + 1 × 32.06 + 4 × 16.00

= 78.20 + 32.06 + 64.00

= 174.26 g/mol

Now, to find the weight percentage of sulfur (S) in K2SO4, use the formula:

Weight % of S = Molar mass of S / Molar mass of K2SO4

Plug in values:

Weight % of S = 32.06 / 174.26 × 100 ≈ 18.41%

So, the correct option is:

b. 18.4%