Question

15.00 mL of an unknown solution of HCl is titrated with 23.45 mL of 0.250 M NaOH solution. Determine the

concentration of the unknown HCl solution?

Answer 1

To determine the concentration of the unknown HCl solution, you can use the concept of stoichiometry. The concentration of the NaOH solution can be calculated using the formula (volume of HCl solution in L) x (concentration of HCl solution) = (volume of NaOH solution in L) x (concentration of NaOH solution). Substituting the known values, we find that the concentration of the NaOH solution is 0.131 M.

Step-by-step explanation:

In a titration, the reactants involved are HCl and NaOH. The balanced chemical equation is:

HCl + NaOH → NaCl + H2O

From the given information, we know that 25.00 mL of HCl solution with a concentration of 0.1234 M is neutralized by 23.45 mL of NaOH.

To determine the concentration of the NaOH solution, we can use the concept of stoichiometry.

To determine the concentration of the NaOH solution, we can use the formula:

moles of HCl = moles of NaOH

moles of HCl = (volume of HCl solution in L) x (concentration of HCl solution)

moles of NaOH = (volume of NaOH solution in L) x (concentration of NaOH solution)

From the equation, we know that 1 mol HCl reacts with 1 mol NaOH.

Therefore, the moles of HCl reacted is equal to the moles of NaOH used.

Using the formula:

(volume of HCl solution in L) x (concentration of HCl solution) = (volume of NaOH solution in L) x (concentration of NaOH solution)

We can substitute the known values into the equation:

(0.025 L) x (0.1234 M) = (0.02345 L) x (concentration of NaOH solution)

Solving for the concentration of NaOH solution:

concentration of NaOH solution = (0.025 L) x (0.1234 M) / (0.02345 L)

concentration of NaOH solution = 0.131 M