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1 vote
What must be true if x/y
? Assume a
0, b0, and y0.

1 Answer

5 votes

The equation simplifies to
\(x = (9a^2)/(b^2)\). Therefore, the correct statement is
\((x)/(y) = (9a^2)/(b^2)\) when the expression
\((x)/(y) / (3a)/(b) = (3a)/(b)\) holds true.

Let's analyze the given equation and the options:


\[ (x)/(y) / (3a)/(b) = (3a)/(b) \]

To solve this, we can simplify the expression on the left by multiplying by the reciprocal of the divisor:


\[ (x)/(y) * (b)/(3a) = (3a)/(b) \]

Now, simplify:


\[ (xb)/(3ay) = (3a)/(b) \]

To isolate x, multiply both sides by
\((3ay)/(b)\):


\[ xb = ((3a)^2)/(b) \]


\[ xb = (9a^2)/(b) \]

Now, divide both sides by b:


\[ x = (9a^2)/(b^2) \]

So, the correct option is:


\[ (x)/(y) = (9a^2)/(b^2) \]

The probable question may be:

What must be true if (x)/(y)-:(3a)/(b)=(3a)/(b) ? Assume a!=0,b!=0, and y!=0. x=y x=0 (x)/(y)=(b^(2))/(9a^(2)) (x)/(y)=(9a^(2))/(b^(2))

User Taniya
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