Question

Light of wavelength 425.0 nm in air falls at normal incidence on an oil film that is 850.0 nm thick. The oil is floating on a water layer 1500 nm thick. The refractive index of water is 1.33, and that of the oil is 1.40. The number of wavelengths of light that fit in the oil film is closest to:

Answer 1

in oil film λ = 303.57 10⁻⁹ m

in the water film λ = 319.55 10⁻⁹ m

Step-by-step explanation:

When electromagnetic radiation reaches a material, its propagation is by a process that we call absorption and reflection,

when light reaches a surface it has a mass much greater than the mass of the photons (m = 0), therefore there is an elastic collision where the frequency does not change, due to the speed of light in the material medium changes, therefore the only possibility is that the wavelength in the material changes, to maintain the relationship

v = λ f

in the void we have

c = λ₀ f

we divide the two expression

c / v = λ₀ / λ

the refractive index is

n = c / v

n = λ₀ /λ

λ = λ₀ / n

let's calculate

in oil film

λ = 425 10⁻⁹ / 1.40

λ = 303.57 10⁻⁹ m

in the water film

λ = 425 10⁻⁹ / 1.33

λ = 319.55 10⁻⁹

those wavelengths are in the ultraviolet