Question

What are the roots of the quadratic equation y=x^2-10x+125

Answer 1

B. x = 5 ± 10i

Explanation:

ax² + bx + c = 0

quadratic formula = (-b ±
`\sqrt{b^(2)-4ac }`)/2a

y = x² - 10x + 125

substitute the values:

(-(-10) ±
`\sqrt{(-10)^(2)-4(1)(125) }`)/2(1)

= (10 ±
`√(100 - 500)`)/2

= (10 ±
`√(-400)`)/2

= (10 ± 20i)/2

= 5 ± 10i

Answer 2

B would be the answer to this quadratic equation.