The addition of 6/(3x² -18x) + 2/3x gives (2x - 6)/(3x² - 18x)
The subtraction of 6x/(6x + 8) - 3/2 gives (-3x - 12)/6x +8
How to add and subtract algebraic fractions
Given
6/(3x² -18x) + 2/3x
Let the LCM be 3x² - 18x
{6 + 2(x - 6)}/3x² - 18x
{6 + 2x - 12}/3x² - 18x
(2x - 6)/(3x² - 18x)
The addition of 6/(3x² -18x) + 2/3x gives (2x - 6)/(3x² - 18x)
Subtract 6x/(6x + 8) - 3/2
Let the LCM be 6x + 8
Multiple each term by 6x + 8
6x(1) - 3(3x + 4)/6x + 8
(6x -9x - 12)/6x + 8
(-3x - 12)/6x +8
The subtraction of 6x/(6x + 8) - 3/2 gives (-3x - 12)/6x +8